The tens place digit of a two - digit number is twice the digit of unit place digit. The number obtained by interchanging the digits diminished the original number by 36. Find the number.
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let the digit at unit place be x
so, digit at tens place = 2x
Number formed = 10(2x) + x = 20x + x = 21x
By interchanging digits,
digit at ones place = 2x
digit at tens place = x
Number formed = 10x + 2x = 12x
According to the question,
21x - 12x = 36
9x = 36
x = 36/9 = 4
x = 4
Original number = 84
so, digit at tens place = 2x
Number formed = 10(2x) + x = 20x + x = 21x
By interchanging digits,
digit at ones place = 2x
digit at tens place = x
Number formed = 10x + 2x = 12x
According to the question,
21x - 12x = 36
9x = 36
x = 36/9 = 4
x = 4
Original number = 84
kaushalsingh122:
nice answer
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