Question

The tens placed digit of the integral part of 48.392 is
1.1
2.2
4.4
5.5
​

Answer 1

Answer:

ANSWER

60

12

+60

−12

−60

−15

⇒ Intergal part of

′

x

′

will have 22 digits

Number of digits in intergal parts =?

So, (60)

12

+

(60)

12

1

−

(60)

15

1

for a shortcut method as we can see the major effect on the total of above expression will be given by (60)

12

So, let x=60

12

taking log of both rides we get

logx=12log60

=12(log2+log3+log10)

=12[0.3030+0.97771+1]

logx=21.3612

⇒x=(10)

21.3612

x≃2.2908×10

21

number of digits will be 22