the tense digit of two digit number is 4 times the digit at the ones place . if the digits are reversed and the resultant number is added to the original number , then sum is 110 . find the original number.
Answers
Answered by
0
Answer:let xy be two digit number
Step-by-step explanation:x=4y_ 1
10x+y+10y+x=110
11x+11y=110
x+y=10_2
From _1and_2
5y=10
Y=2 and x=8
Answered by
0
Answer:
82
Step-by-step explanation:
- let the original no=10x+y
- According to question
x=4y
when digit are reversed then the number is 10y+x
- when original and reversed digits are added then we get
10x+y+10y+x=110
11x+11y=110
11(x+y)=110
x+y=10
putting x=4y
4y +y=10
5y=10
y=2
then x=4y ;4×2=8
original no =10x+y
i.e 10×8+2
82 answer
Similar questions