Question

the tense digit of two digit number is 4 times the digit at the ones place . if the digits are reversed and the resultant number is added to the original number , then sum is 110 . find the original number. ​

Answer 1

Answer:let xy be two digit number

Step-by-step explanation:x=4y_ 1

10x+y+10y+x=110

11x+11y=110

x+y=10_2

From _1and_2

5y=10

Y=2 and x=8

Answer 2

Answer:

82

Step-by-step explanation:

• let the original no=10x+y
• According to question

x=4y

when digit are reversed then the number is 10y+x

• when original and reversed digits are added then we get

10x+y+10y+x=110

11x+11y=110

11(x+y)=110

x+y=10

putting x=4y

4y +y=10

5y=10

y=2

then x=4y ;4×2=8

original no =10x+y

i.e 10×8+2

82 answer