Physics, asked by tamannasanger, 6 months ago

The tension in the string connecting the blocks A and B kept on smooth surface is
(3) 2 m/s
(1) 4 m/s
(4) 10 m/s
А
B
2 kg
3 kg
F = 5 N
(4) 2N
(1) 5N
(2) 1 N
(3) 3 N
sion in the string AB is (pulley and string are massless)​

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Answers

Answered by shubham0204
24

Answer:

See below.

Explanation:

Please refer to the image attached to this answer.

Let the blocks move with acceleration 'a'. Let T be the tension in the string connecting the blocks.

Hence, for block A ( refer to the FBD in the image ),

2a = T

For block B,

3a = 5 - T

Solving both the equations,

3a = 5 - ( 2a ) \\ 5a = 5\\\implies a = 1 \ ms^{-2}

Using equation 1, the tension in the string will be,

T = 2a\\T = 2 \ N

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