The tent of height 8.25 m is in the form of a right circular cylinder with diameter 30 m and height 5.5 m surrounded by a right circular cone of same base find the cost of canvas of the tent at the rate of 45 rupees per metre square
Answers
The cost of canvas of the tent at the rate of 45 rupees = 122,505.52 Rs.
Step-by-step explanation:
Given:
The height of tent for right circular cylinder, h = 5.5 m,
The Base diameter of Cylinder,d = 30 m,
the base radius of Cylinder, r = 15 m,
The height of the conical tent can be found as:
The height of the conical tent = 8.25 - 5.5= 2.75 m
Now we can calculate the total surface area of the tent as:
slant height of cone, l = = 16.77m
So the total surface area of tent =
Now we can calculate the total cost of canvas to be used in tent =
the cost of canvas of the tent at the rate of 45 rupees = 122505.52 Rs.
The cost of canvas is Rs. 55,687.5
Height of the tent = 8.25 m (Given)
Height of cylindrical = 5.5 m (Given)
Diameter of the cylinder = 30 m (Given)
Thus, Radius of the cylinder , r = 30 / 2 = 15 m
Let cone's slant height be = l
Therefore,
Height of the right circular cone -
= 8.25 - 5.5
= 2.75 m
Now,
l = √r² + h²
l = √(15)² + (2.75)²
l = √225 + 7.5625
l = 15.25
Total curved surface area of tent = Curved surface area of cylinder + Curved surface area of cone
= 2πrh + πrl
= πr(2h + l)
= π ×15 × (2 × 5.5 + 15.25)
= π × 15(11 + 15.25)
= 22/7 × 15 × 26.25
= 1,237.5
Therefore, the total curved surface area of the tent = 1,237.5 m²
Rate of canvas = Rs. 45 per m²
Cost of canvas of tent
= 1,237.5 m² × 45
= 55,687.5
Therefore, the cost of canvas is Rs. 55,687.5