The tenth term from the end of the ap 4 9 14 ........ 254 is
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a = 4
d= 9-4 = 5
a n=254
=>a + (n-1) d = 254
=> 4 + (n-1)5 =254
=>(n-1)5 = 250
=>n-1=50
=>n=51
Therefore there are 51 terms in the given A.P. which se get as 254
51-10 = 41 So, se NEED to find the 41st term of the given A.P.
a 41 = a + 40*d = 4 + 40 * 5 = 4 + 200 = 204
d= 9-4 = 5
a n=254
=>a + (n-1) d = 254
=> 4 + (n-1)5 =254
=>(n-1)5 = 250
=>n-1=50
=>n=51
Therefore there are 51 terms in the given A.P. which se get as 254
51-10 = 41 So, se NEED to find the 41st term of the given A.P.
a 41 = a + 40*d = 4 + 40 * 5 = 4 + 200 = 204
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