The tenth term of an AP is 30 and the eleventh term is 50. Find the AP.
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Given: 6th term A6= 20, 11th term A11=30
we have, An= A1+(n-1)d
=> A6=A1+(6–1)d
=> 20=A1+5d ——equation (1)
A11=A1+(11–1)d
=> 30=A1+(11–1)d
=> 30= A1+10d ——equation (2)
equating 1 and 2, we have
=> d=2, substitute in eq(1)
=> 20= A1+5(2)
=>A1=20–10=10
Hence, the first term A1=10 and common difference d=2.
Step-by-step explanation:
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