The tenth term of an arithmetic progression is 125 and the sum of the first ten terms is 260. Given that the first term is -73, find the common difference
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Answered by
0
Answer:
d=22
Step-by-step explanation:
a = -73
a + 9d = 125
hence, d =22
Answered by
1
Answer:
Given that: t1 + t3 + t5 = 39 t2 + t4 + t6 = 51 To find: t10 = ? Solution:Let a be the first term and d be the common difference. t1 + t3 + t5 = 39
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