The tenth term of an arithmetic sequence is 71 and common difference is 4. Find 18th and 6th terms.
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Answer:
18th term:103,6th term = 55
Step-by-step explanation:
d= 4
nth term is a+(n-1)d where a is the first term.
a+36 =71
a = 35
18th term = a + 17d = 35+17(4)=35+68=103
6th term = a + 5d = 35+5(4)=55
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