The tenth term of ap -3, -1, 1,3 ...., is
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||Required Solution||
-3,-1,1,3.... are in AP
a = -3
a1 = -1
a2 = 1
a3 = 3
- d = a1-a
Where, d is the common difference.
→ -1-(-3)
→ -1+3
→ 2
- Sum of n terms = a+(n-1)d
→ -3+(10-1)2
→ -3+(9)2
→ -3+18
→ 15
- 10th Term of the AP ☞ 15
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