The term independent of x in (3x−5x2)9
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Answer:
(-10×3)×9
(-30) 9
-30×9
-270
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(3X--5 X^ --2) ^9
General term in BINOMIAL expansion is
=Tr+1 term = ncr X^n-r a^r
n=9 p=1 q=2
r = np/p+q = 9×1/1+2 =9/3=3
The independent term is
9c3 (3x)^6 (--5/x^2)^3
84 3^6 X^6 (-5) ^3 ×1/x^6
=84 3^6 × (-5)^3 = 84 ×729× -125= --7654500
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