The term not containing x in expansion of (1-x)^2 (x+1/x)^10 is
Answers
Answered by
1
Answer (1−2x+x
2
)(x+
x
1
)
10
=(x+
x
1
)
10
−2x(x+
x
1
)
10
+x
2
(x+
x
1
)
10
For (x+
x
1
)
10
T
r+1
=
10
C
r
x
10−2r
Then the coefficient of term independent of x will be the sum of the coefficient of x independent terms in (x+
x
1
)
10
, 2x(x+
x
1
)
10
and x
2
(x+
x
1
)
10
Therefore
(x+
x
1
)
10
−2x(x+
x
1
)
10
+x
2
(x+
x
1
)
10
=
10
C
5
+0+
10
C
6
...(0 since there are no independent terms in 2x(x+
x
1
)
10
)
=
10
C
5
+
10
C
6
=
11
C
5
Step-by-step explanation: Please check the link and get the answer
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