The terminal of a 18v battery with an internal resistance of 24ohm are connected to a circular wire of resistance 24 ohm at two distant at one quarter of the circumference of a circular wire.the current though the bigger arc of the circle will be
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Answered by
1
Hi..
Imain=18×257=36/57A ...
Hope this helps u!!
Imain=18×257=36/57A ...
Hope this helps u!!
Answered by
10
hey mate
here is your ans
given : V= 18v
R= 24 ohm at two distant at one quarter of the circumference of circular wire so
R will be 1/4*24 so we get R = 6 ohm
we know that
V= IR
I = V/ R
I = 18/ 6
I = 3 A.
hope it help yu
here is your ans
given : V= 18v
R= 24 ohm at two distant at one quarter of the circumference of circular wire so
R will be 1/4*24 so we get R = 6 ohm
we know that
V= IR
I = V/ R
I = 18/ 6
I = 3 A.
hope it help yu
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