Question

The terminal potential deffrence across the heater drawing a current of 8A from a battery is 48V. what current will the heater draw when it is connected across a battery of 129V?​

Answer 1

Answer:

$\bigstar{\bold{Current=21.5\:A}}$

Explanation:

$\Large{\underline{\underline{\it{Given:}}}}$

• Initial Potential difference  = 48 V
• Initial Current  = 8 A
• Final potential difference = 129 V

$\Large{\underline{\underline{\it{To\:Find:}}}}$

• Final current

$\Large{\underline{\underline{\it{Solution:}}}}$

➛ Here we have to first find the resistance of the heater

➛ We know by Ohm's law

    R = V/I

➛ Substituting the data we get,

    R = 48/8

    R = 6

➛ Hence the resistance of the heater is 6 Ω

➛ Now we have to find current flowing through the heater

➛ Again by Ohm's law,

   I = V/R

➛ Substituting the data,

   I = 129/6

   I = 21.5

➛ Hence current through the heater is 21.5 A

   $\boxed{\bold{Current=21.5\:A}}$

$\Large{\underline{\underline{\it{Notes:}}}}$

➛ Ohm's law state that the potential difference acrooss a conductor is directly proportional to the current flowing through it and the resistance of the conductor.

V = I R