Question

The terminal velocity of the lead sphere is given by V equal to mass times gravity divided by 6 pie kr
Where K is constant that determines viscous drag to motion in the fluid.
M is the mass of the sphere
r is the radius of the sphere
g is acceleration due to gravity
Determine the units of k.

Answer 1

Answer:

T

∝m

α

η

β

r

γ

g

k

M

0

L

1

T

−1

=(M

1

)

α

(M

1

L

−1

T

−1

)

β

(L

1

)

γ

(LT

−2

)

k

0=α+β⇒α=1=k

1=−β+γ+kβ=γ=−1

−1=−β−2k

⇒V

T

∝

ηr

mg

Thank you