Question

The terminal voltage of a cell of emf e on short circuiting will be

Answer 1

Explanation:

During a short-circuit, 'theoretically' current becomes infinite. But what about the emf? My attempt:

Since the potential difference is zero..

hope it helps uuh... ❤✌

Answer 2

Answer:

The terminal voltage of a cell of emf e on short-circuiting will be zero.

Explanation:

The terminal potential difference of a cell when its short-circuited exists is zero. Terminal voltage exists consistently lower than the emf of the cell. It exists because of the drop in potential difference because of the current passing through the internal resistance of the cell or the generator. They exist as described by the equation E=V + Ir, where, I exist as the current and r exists internal resistance of the cell. The terminal voltage of the cell exists shorter than its emf as the cell emf which exists obtained in the dielectric in the direction opposite to the direction of the external terminal voltage.

When a cell exists short-circuited it provides a sense that the current in the circuit exists equivalent to zero and as you see in the (E = EMF of the cell) equations that in both issues if the current exists equivalent to zero then the terminal potential exists equivalent to the potential of the cell or the EMF of the cell.

Hence, in short-circuiting

I=0, so V=0

Therefore, the terminal voltage of a cell of emf e on short-circuiting will be zero.

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