Physics, asked by mischievousgirl6247, 7 months ago

The terminals of a battery of emf 3 V and internal resistance 2.5 ohm
are joined to the diagonally opposite corners of a cubical skeleton frame of 12 wires, each of resistance. Find the current in the battery.

Answers

Answered by zai908494

1

Answer:

Explanation:

Using KVL, 6−2=(1+3)I or I=1A

Thus terminal potential of battery 2 is V

2

=2+3I=2+3=5V

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