The Tetrahedron Superyacht designed by Jonathan Schwinge is a regular tetrahedron with edges 20\,\text{m}20m20, start text, m, end text long. The distance rrr from one corner to the center of the base (shown in the picture below) is 11.5\,\text{m}11.5m11, point, 5, start text, m, end text.
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Answered by
15
Answer:
The vertical height of Tetrahedron is 16.4 m
Step-by-step explanation:
To solve this we use the Pythagoras theorem which
Hypotenuse² = Perpendicular² + Base²
Now as per the given information,
Hyp = 20
Base = 11.5
Putting the above in formula
(20)² = P² + (11.5)²
P² = (20)² - (11.5)²
P² = 400 - 132.25
P² = 267.75
P = sqrt{267.75}
P = h = 16.36 m
The vertical height of Tetrahedron is 16.4 m
Answered by
4
Answer:
16.4m
Step-by-step explanation:
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