Question

The $K_{sp}$ for Cr(OH)₃ is 1.6 × 10⁻³⁰. The solubility of this compound in water is :
(a) $\sqrt[4]{1.6 x 10^{-30}}$
(b) $\sqrt[4]{1.6 x 10^{-30} / 27}$
(c) $1.6 x 10^{-30/27}$
(d) $\sqrt{1.6 x 10^{-30}}$

Answer 1

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