The texi fare in city is as follows:for the first kilometer the fare is Rs 8 and for the value a subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write the linear equation for this variable fir thia information
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Answered by
2
linear equation will be..
8+5(X-1)=Y
I hope now u r understand.
8+5(X-1)=Y
I hope now u r understand.
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kanishka1245:
Pls tell in detail
Answered by
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Total distance covered = x km
Fare for 1st kilometre = Rs 8
Fare for the rest of the distance = Rs (x − 1) 5
Total fare = Rs [8 + (x − 1) 5]
y = 8 + 5x − 5
y = 5x + 3
5x − y + 3 = 0
It can be observed that point (0, 3) and (-3/5, 0)satisfies the above equation.
Therefore, these are the solutions of this equation.
The graph of this equation is constructed as follows.
Here, it can be seen that variable x and y are representing the distance covered and
the fare paid for that distance respectively and these quantities may not be negative.
Hence, only those values of x and y which are lying in the 1st quadrant will be
considered.
Fare for 1st kilometre = Rs 8
Fare for the rest of the distance = Rs (x − 1) 5
Total fare = Rs [8 + (x − 1) 5]
y = 8 + 5x − 5
y = 5x + 3
5x − y + 3 = 0
It can be observed that point (0, 3) and (-3/5, 0)satisfies the above equation.
Therefore, these are the solutions of this equation.
The graph of this equation is constructed as follows.
Here, it can be seen that variable x and y are representing the distance covered and
the fare paid for that distance respectively and these quantities may not be negative.
Hence, only those values of x and y which are lying in the 1st quadrant will be
considered.
Attachments:
![](https://hi-static.z-dn.net/files/def/691ee444faec8f36bd6e89f2240c6d21.jpg)
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