Question

the
The 17
term of an A.P. ecceeds
the 10th terms by 7. Find the common difference
​

Answer 1

Answer:

d = (7-n)/7

Step-by-step explanation:

n17= n+16d

n10= n+9d

ATQ

n+16d= n+9d +7

n+(16-9)d = 7

n+7d = 7

7d = 7-n

d = (7-n)/7

Answer 2

Answer:

1

Step-by-step explanation:

Given that the 17th term of an A.P exceeds its 10th term by 7 .  

d = ?

⇒a+16d = 1+9d+7

⇒16d-9d = 7

⇒7d = 7

⇒d = 7/7 = 1 .

Therefore , common difference = 1