the the age of father and his son and respectively 4 4and 8 years in how many years hence will be father be 4 time old the son
Answers
Answered by
2
Answer:
let after "x" years age of father is 4 times age of son
44+x=4(8+x)
=32+4x
44-32=4x-x
12=3x
x=12/3
x=4
hence after 4 years father's age 48 and sons age is 12
Answered by
0
Answer:
After 4 years, the father will be 4 times the age of his son.
Explanation:
Let the years after which the father becomes 4 times the age of his son
be x.
Given:
Age of father = 44
age of his son = 8
solution:
→(44 + x) = (8 + x)4
→44 + x = 32 + 4x
→12 = 3x
→4 = x
Hence, the value of x is 4 yrs.
Verification:
father = (son)4
48 = (12)4
48 = 48
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