Question

the the age of father and his son and respectively 4 4and 8 years in how many years hence will be father be 4 time old the son​

Answer 1

Answer:

let after "x" years age of father is 4 times age of son

44+x=4(8+x)

=32+4x

44-32=4x-x

12=3x

x=12/3

x=4

hence after 4 years father's age 48 and sons age is 12

Answer 2

Answer:

After 4 years, the father will be 4 times the age of his son.

Explanation:

Let the years after which the father becomes 4 times the age of his son

be x.

Given:

Age of father = 44

age of his son = 8

solution:

→(44 + x) = (8 + x)4

→44 + x = 32 + 4x

→12 = 3x

→4 = x

Hence, the value of x is 4 yrs.

Verification:

father = (son)4

48 = (12)4

48 = 48