Math, asked by pritish7, 1 year ago

the the first and last term of an A.P are 17 and 350 respectively.If the c.d is 9 how many terms are there and what is their sums

Answers

Answered by simran206
2
sorry , Sn = 19(367)
Sn = 6937
so , sum = 6973
Hope it is helpful to u☆☆
Attachments:

Abhirup111: If there are n numbers of terms then
17+{(n-1)×9}=350
{(n-1)×9}=333
(n-1)=37
n=38
So there are 38 terms.Including 17and 350
Summation of the all terms is:-->
(38/2)×(350+17)=(19×367)
Answered by Anonymous
1

\bf\huge\boxed{\boxed{\bf\huge\:Hello\:Mate}}}



\bf\huge Let\: a\: first\: terms\: and\: CD\: be\: D \:and\: L\: be\: last\: term



\bf\huge a = 17 , L = a_{n} = 350 and D = 9



\bf\huge According\:to\:the\:Question



\bf\huge => a_{n} = l = 350



\bf\huge => a + (n - 1)d = 350



\bf\huge => 17 + (n - 1)9 = 350



\bf\huge => 9(n - 1) => 350 - 17 = 333



\bf\huge => n - 1 = \frac{333}{9} = 37



\bf\huge => n = 37 + 1 = 38



\bf\huge Substitute\:a = 17 , l = 350 \:and\: n = 38



\bf\huge S_{n} = \frac{N}{n}(a + l)



\bf\huge S_{38} = \frac{38}{2}(17 + 350)



\bf\huge = 19\times 367



\bf\huge = 6973



\bf\huge\boxed{\boxed{\:Regards=\:Yash\:Raj}}}


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