Question

the
- The focal length of converging lens is 20cm.2cm
height object is room from the lens where will
image
be formed and what kind of image
is it? And also find the height of the image!
hint: A deal, diminished, invested image formed
at 30cm from the lens.​

Answer 1

Step-by-step explanation:

Given : f = 20cm, h = 2cm, v = 30cm

To find : u, h' and nature of image

Solution : 1/f = 1/v - 1/u

1/f - 1/v = -1/u

1/20 - 1/30 = -1/u

-1/u = 3/60 - 2/60

-1/u = 1/60

u = -60cm

h'/h = v/u

h'/2 = 30/-60

h'/2 = -1/2

2h' = -2

h' = -2/2

h' = -1cm

Image formed is real and inverted.

Answer 2

Step-by-step explanation:

1/f . 1/ v - 1/u

• 1/u = 1/f + 1/ u = 1/20cm + 1/-30 cm = 1/ 20 cr

= 3-2/ 60 cm

= 1/60 cm

v= 60 cm , v is positive. The image will be formed at 60 cm from the lens and on the other side of the lens with respect to the object. It is a real image.

h2/h1=u/v

h2/2cm =60cm/-30 cm

= -2

h20 = -2×2cm= -4cm

h2

is negative. This shows that the image is inverted . The height of the image = - 4 cm

M= h2/h1

= -4cm/2cm

= -2cm

M is negative, indicating that teh image is inverted. <br> The magnification produced by the lens = -2

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