Question

The the length of a rectangular park is two times its breadth if the perimeter of the park is 192 find its dimension of park

Answer 1

Answer :

Length of the rectangular park is 64 cm and the breadth of the rectangular park is 32 cm.

Given :

• The length of a rectangular park is 2 times of its breadth .
• Perimeter of the park is 192 cm.

To find :

• The dimensions of the park.

Solution :

Consider,

• Breadth of the rectangular park = x cm
• Length of the rectangular park = 2x cm.

Formula used :-

${\boxed{\sf{Perimeter\:of\: rectangle=2(length+breadth)}}}$

According to the question :-

$\to\sf{2(2x+x)=192}$

$\to\sf{2x+x=96}$

$\to\sf{3x=96}$

$\to\sf{x=32}$

• Breadth of the rectangular park = 32 cm.

★ Length of the rectangular park = 2×32 = 64 cm.

________________________

★ Verification ★

• Length = 64 cm
• Breadth = 32 cm

Perimeter = 192

→ 2(64+32)=192

→ 2 × 96 = 192

→ 192 = 192

Hence Verified !

Answer 2

Answer:

The dimension of the park is:

Step-by-step explanation:

The length of a rectangular park = 2(the breadth of a rectangular park)

the perimeter of the park = 192 cm

To find:

the dimension of the park

Formula:

the perimeter of a rectangle= 2(length+breadth)

• let the breadth of a rectangle be 'x'
• therefore, length = 2x (twice the breadth)

the perimeter of a rectangular park = 192

by the formula,

2(l+b) :

2(2x+x) = 192

2(3x) = 192

6x = 192

x = 32

breadth(x) = 32 cm

length(2x) = 32*2 = 64 cm

therefore, length = 64cm & breadth = 32cm

verification:

2(l+b) = 192

2(64+32) = 192

2(96) = 192

192 = 192

Hence proved.

Note:

Units are very important in the problems.