The the length of a tangent from a point a at a distance 5 cm from the centre of the circle is 4 cm find the radius of the circle
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Here, AB is the tangent that is drawn on the circle from a point A.
So, the radius OB will be perpendicular to AB i.e. OB ⊥ AB
We know, OA = 5cm and AB = 4 cm
Now, In △ABO,
OA2 =AB2+BO2 (Using Pythagoras theorem)
52 = 42+BO2
BO2 = 25-16
BO2 = 9
BO = 3
So, the radius of the given circle i.e. BO is 3 cm.
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