The the length of rectangle is 7 times its breadth if the perimeter of the rectangle is 208 CM its length will be
Answers
Question
The length of rectangle is 7 times its breadth if the perimeter of the rectangle is 208 CM its length will be ?
Solution
Given :-
- The length of rectangle is 7 times its breadth
- the perimeter of the rectangle is 208 cm
Find :-
- Length of rectangle
Explanation
Let,
- Breadth is x cm
So, The length of rectangle is 7 times its breadth
==> Length = 7x.
Using Formula
★ Perimeter of rectangle = 2 * [ Length + breadth ]
Keep value of Length & breadth
==> Perimeter of rectangle = 2 * [ x + 7x ]
==> 208 = 2 * 8x
==> 8x = 208/2
==> 8x = 104
==> x = 104/8
==> x = 13 cm
Hence
- Length of rectangle = 7x = 7 * 13 = 91 cm
- Breadth of rectangle = x = 13 cm
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✬ Length = 91 cm ✬
Step-by-step explanation:
Given:
- Length of a rectangle is 7 times it's breadth.
- Perimeter of rectangle is 208 cm.
To Find:
- What is the measure of length of rectangle ?
Solution: Let the breadth of rectangle be x cm. Therefore,
- Length = 7 times of x = 7x cm
As we know that :-
★ Perimeter of rectangle =2(Length + Breadth)★
But perimeter = 208 cm
A/q
2 ( 7x + x ) = 208 cm
2 8x = 208
16x = 208
x =
x = 13 cm
Hence, Breadth of rectangle = x = 13 cm
Length of rectangle = 7x = 7(13) = 91 cm.
_____________________
★ Verification ★
➯ 2(Length + Breadth) = 208
➯ 2(91 + 13) = 208
➯ 2 104 = 208
➯ 208 = 208 { Verified }