The the perimeter of a rectangle is 5270 where length is 60 more than its breadth and dimension of rectangle is
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Let the breadth of the rectangle be x units and its length be (x+60) units
Perimeter = 5270 units
ATQ, 2 ( x+x+60) = 5270 units
=>4x + 120 = 5270 units
=> 4x = 5270-120 units
=> x= 5150/ 4 units = 1287.5 units
Length= (1287.5+ 60) units = 1347.5 units
Breadth = 1287.5 units . (Answer)
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