Question

the
the perpendicular drawn from the extremities of the base of the isosceles triangle to the opposite side are equal
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Answer 1

Answer:

In ∆ABC

AB=AC

Angle B=angle C

BD is perpendicular to AC

CE is perpendicular to AB

Required to prove BD=CE

Step-by-step explanation:

In∆BCE and ∆CBD

angle BCE= angle CBD

angle BEC =angle CDB

Side BC =Side BC

therefore∆BCE congruent to ∆CDB (byAAS)

this implies BD=CE (cpctc)