Question

the the population of a town increased by 3whole 1 by 2% of its value at the beginning of each year if the present population of a town is 8869 743 find the population of the town 3 years ago​

Answer 1

Step-by-step explanation:

The population of a town increases by 3\frac{1}{2}\%3

2

1

% of it's value at the beginning of each year. If the present population of the town is 8869743.

To find : The population of the town three years ago ?

Solution :

The population is given by,

N=N_o(1+r)^tN=N

o

(1+r)

t

The initial population is N_o=8869743N

o

=8869743

The rate is r=3\frac{1}{2}\%=\frac{7}{2}\%=0.035r=3

2

1

%=

2

7

%=0.035

The time is t=3 years

Substitute the value in the formula,

N=8869743(1+0.035)^3N=8869743(1+0.035)

3

N=8869743(1.035)^3N=8869743(1.035)

3

N=8869743\times 1.108717875N=8869743×1.108717875

N=9834042.61076N=9834042.61076