Question

the the sum of three consecutive multiplies of 8 is 888 find the multiplies ​

Answer 1

Answer:

Step-by-step explanation:

Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 888

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

Take 24 on the RHS

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304

If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

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Answer 2

Answer:

Step-by-step explanation:

let the no.s be x,x+1 and x+2

8x+8(x+1)+8(x+2)=888

=8x+8x+8+8x+16=888

=24x+24=888

=24x=888-24

=24x=864

=x=864÷24

=x=36

now the no.s are 288,289 and 304