The thickness of a hollow metallic cylinder is 2 cm. It is 42cm long and its inner radius is 10cm. Find the volume of metal required to make the cylinder, assuming it is open at both the ends.
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Answered by
2
Answer:
Step-by-step explanation:
Thickness of cylinder =2cm
Length of cylinder (h) =70cm
Outer Radius (R) =14cm
Then inner Radius(r) =outer Radius - thickness
=14-2
=12cm
Volume of hollow cylinder
=11440cm³
Weight of 1cm³=8gm
So weight of 11440cm³=11440x8
=91520gm
=91520/1000
=91.52kg (1kg=1000gm)
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Answered by
8
Answer:
5720 cm^3
Step-by-step explanation:
height=35cm
radius=12cm
thickness=2cm
outer radius=12+2=14cm
volume of metal required to make the cylinder
= π(R^2-r^2)h
=22/7{(14*14)-(12*12)}35
=22*(196-144)*5
=110*52
=5720 cm^3(answer)
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