Question

the thickness of a hollow metallic cylinder is 2 cm It is 35 cm long and its inner radius is 12 cm find the volume of metal required to make the cylinder it is open at either end

Answer 1

Volume of metal required is
π(r1-r2)^2 ×h
3.14 × 4 × 35
439.6 cucm

Answer 2

hello dear

Answer:

$\huge \bold{5720 {cm}^{3} }$

Step-by-step explanation:

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thickness of hollow cylinder is 2 cm

length=35cm

Inner radius=12cm

outer radius=12+2=14cm

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volume volume of wood required to make the cylinder = volume of whole cylinder - volume of hollow cylinder.

$\pi \times {r}^{2} \times h - \pi \times {r}^{2} \times h$

$= \: \: \pi( {r}^{2} - {r}^{2} )h$

$= \frac{22}{7} ( {14}^{2} - {12}^{2} )35$

$= \frac{22}{7} (196 - 144)35$

$= \frac{22}{ \cancel7} \times 52 \times \cancel35$

$= 22 \times 52 \times 5$

$= 5720 {cm}^{3}$

$\bf{hope \: this \: helps \: you }$