the thickness of a hollow metallic cylinder is 2 cm . It is 70 cm long with outer radiusof 14 cm . Find the volume of the metal used in making the cylinder ,assuming that it is open at both ends . Also find its weight if the metalbweights 8 g per cm^3
Answers
Answer:
Let t is thickness of the cylinder
r
1
is outer radius of the cylinder
r
2
is inner radius of the cylinder
h is height of the cylinder
∴t=2cm
r
1
=14cm
h=70cm
Now, inner radius is calculated as,
r
2
=r
1
−t
∴r
2
=14−2=12cm
1) Volume of the hollow cylinder is given by,
V=c/sarea×heightofcylinder
∴V=(πr
1
2
−πr
2
2
)×h
∴V=π(14
2
−12
2
)×70
∴V=
7
22
(196−144)×70
∴V=22×52×10
∴V=11440cm
3
2) Given wright of the metal, ρ=8
cm
3
g
Let m = mass of the cylinder
∴ρ=
V
m
∴8=
11440
m
∴m=8×11440
∴m=91520gm
∴m=91.520kg
Answer:
Let t is thickness of the cylinder
r
1
is outer radius of the cylinder
r
2
is inner radius of the cylinder
h is height of the cylinder
∴t=2cm
r
1
=14cm
h=70cm
Now, inner radius is calculated as,
r
2
=r
1
−t
∴r
2
=14−2=12cm
1) Volume of the hollow cylinder is given by,
V=c/sarea×heightofcylinder
∴V=(πr
1
2
−πr
2
2
)×h
∴V=π(14
2
−12
2
)×70
∴V=
7
22
(196−144)×70
∴V=22×52×10
∴V=11440cm
3
2) Given wright of the metal, ρ=8
cm
3
g
Let m = mass of the cylinder
∴ρ=
V
m
∴8=
11440
m
∴m=8×11440
∴m=91520gm
∴m=91.520kg