Question

The thickness of a metallic pipe is 1.5 cm it's inner diameter is 21 cm what is tha volume of the metal required for a pipe of length 7 cm

Answer 1

Inner radius = 21/2 = 10.5
Outer radius = 10.5 + 1.5 = 12
Volume = Pi x (r2 squared - r1 squared) x L
             = 22/7 x (144 - 110.25) x 7
               = 742.5 approx.

Answer 2

The volume of metal required for a pipe of length 7 cm with a thickness of 1.5 cm and an inner diameter of 21 cm is approximately 152.25 cubic centimeters (cc) or milliliters (ml).

The volume of the metal required for a pipe can be calculated by finding the difference between the volume of the outer cylinder (with radius = inner radius + thickness) and the volume of the inner cylinder (with radius = inner radius and length = length of the pipe).

The inner radius of the pipe is 21 cm / 2 = 10.5 cm.

The outer radius of the pipe is the inner radius + thickness = 10.5 cm + 1.5 cm = 12 cm.

The length of the pipe is 7 cm.

The volume of the metal required for the pipe is:

= volume of outer cylinder - volume of inner cylinder

= π * outer radius^2 * length - π * inner radius^2 * length

= π *$(12 cm)^2$ * 7 cm - π * $(10.5 cm)^2$ * 7 cm

= $\pi * 144 cm^2 * 7 cm - \pi * 110.25 cm^2 * 7 cm$

= $\pi * 924 cm^3 - \pi * 771.75 cm^3$

=$\pi * (924 cm^3 - 771.75 cm^3)$

= $\pi * 152.25 cm^3$

Therefore, the volume of metal required for a pipe of length 7 cm with a thickness of 1.5 cm and an inner diameter of 21 cm is approximately 152.25 cubic centimeters (cc) or milliliters (ml).

for such more question on diameter

https://brainly.in/question/35524739

#SPJ3