Question

The thickness of a metallic tube is 1 cm and its outer radius is 14 cm .Find the weight of 49 cm long tube? 1cm^3 =8g.

Answer 1

vol of cylinder = 22/7 (14^2-13^2) 49 cm^3

density= mass/volume

mass = 8* vol of cylinder = 4158 gm

Answer 2

Answer:

Weight of the metallic tube is  33233.76 g .

Step-by-step explanation:

As given

The thickness of a metallic tube is 1 cm and its outer radius is 14 cm .

The length of the tube is 49 cm .

Let us assume that the outer radius is defied by R .

Let us assume that the inner radius is defied by r .

Thus

R = 14 cm

r = Outer radius - Thickness of pipe

r = 14- 1

  = 13 cm

$Volume\ of\ the\ pipe = \pi (R^{2}-r^{2})\times h$

$\pi = 3.14$

$Volume\ of\ the\ pipe =3.14\times (14^{2}-13^{2})\times 49$

$Volume\ of\ the\ pipe =3.14\times (196-169)\times 49$

$Volume\ of\ the\ pipe =3.14\times 27\times 49$              

                                            = 4154.22 cm³

As

cm³ = 8g

Weight of the metallic tube = 8 × 4154.22

                                              = 33233.76 g

Therefore the weight of the metallic tube is  33233.76 g .