Math, asked by anuragkumarrtp, 1 year ago

The thickness of a metallic tube is 1cm and its outer radius is 14cm.find the weight of 49cm long tube (1cm^3 of metal weight 8g)

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Answered by alirizvi8860292174
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Secondary SchoolMath 6+3 pts



The length of metallic tube is 1 m,its thickness is 1 cm and its inner diameter is 12 cm.Find the weight of the tube if the density of the metal is 7.7

grams per cubic centimeter.

Report by Tspreethi 08.03.2016

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Alirizvi8860292174 · Ambitious

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adarshkumar610

Adarshkumar610 Ambitious

Inner radius,r=12/2=6cm

thickness=1cm

so,outer radius,R=6+1=7cm

height,h=1m=100cm

volume=pi×(R^2-r^2)×h

=22/7×(7^2-6^2)×100

=22/7×(49-36)×100

=22/7×13×100

286/7×100

=28600/7

since,density=7.7gm/cm^3

also,weight=volume×density

weight=28600/7×7.7gm

=31460gm

or,31.46 kg


anuragkumarrtp: Wrong
anuragkumarrtp: 33.264kg
alirizvi8860292174: Amm....wait let me check it
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