The thickness of a mettalic tube is 1cm and the inner diameter of the tube is 12cm.Find the weight of 1m long tube ,if the density of the metal is 7.8g/cm^3
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firstly find its volume
r1(inner radius of the tube)=12/2=6cm
r2(thickness of the tube)=1cm
R(total radius of the tube)=6+1=7cm
now
(πR²)-(πr1²)
{(22/7)×7²}-{(22/7)×6²}
154-(792/7)
154-113.142857142........
154-113.143
41.143cm²
now multiply it by 1m=100cm
it will be 41.143×100=4114.3cm³
formula of density
d=m/v
78/10=m×41143/10
m=78/41143
r1(inner radius of the tube)=12/2=6cm
r2(thickness of the tube)=1cm
R(total radius of the tube)=6+1=7cm
now
(πR²)-(πr1²)
{(22/7)×7²}-{(22/7)×6²}
154-(792/7)
154-113.142857142........
154-113.143
41.143cm²
now multiply it by 1m=100cm
it will be 41.143×100=4114.3cm³
formula of density
d=m/v
78/10=m×41143/10
m=78/41143
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