Physics, asked by surajr9653, 7 months ago

The thickness of a wire with a
screw gauge is found to be 3.59
mm, 3.61 mm, 3.63 mm, 3.66 mm,
3.58mm, 3.59mm, 3.61 mm, The
true value is
a
3.59
b)
3.61
c) 3.6
d) 3.59​

Answers

Answered by NishantRaj7
0

Explanation:

The separation between the plates of a capacitor of capacitance 2uF is 4 mm. Initially, there is air

between the plate's. If two dielectric slabs of area of cross-section same as the capacitor, thickness 2 mm

each, and dielectric constant 3 and 5 respectively are introduced, the capacitance becomes (in 1F):

(A) 4

(B) 7.5

(C)

8

(D) 15

‍‍

Similar questions