the thickness of the metal of a hemispherical mettalic cup is 1cm.if the capacity of the cup is 343/8, find the quantity of metal required to make it
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Inner radius=24.7cm
Thickness=0.3cm
Outer radius=(24.7+0.3)cm
=25cm
outer surface area of bowl=2πr
2
=2×3.14×25×25
=3925cm
2
cost of polishing 10cm
2
surface area=Rs.4
∴ cost of polishing 3925cm
2
surface area=
10
4×3925
=Rs.1570
Hope it help you first solve the equation then draw the diagram
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