the thickness of the metallic tube is 1 centimetre and inner diameter of the tube is 12 cm find the weight of 1 M long tube if the density of the metal be 7.8 gram per centimetre cube
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Answered by
3
Answer:
Step-by-step explanation:
Density = mass/volume
----------=volume=area×thickness
Mass= density×area×thickness
Area of cylinder= 2pi×radius×length of tube
Mass=7.8×2×3.14×6×100×1
Mass=9360gm
shubhiG:
your ans is wrong
Answered by
8
- inner diameter = 12 cm
Therefore, radius = 6 cm
- Thickness = 1 cm
External radius = thickness + inner radius
=1 + 6 = 7 cm.
- Length of tube = 1 m = 100 cm
Now, volume of tube = π(R² - r²)h
22/7 * (7² - 6²) * 100
22/7 * 13 * 100 = 4085.71 cm³
- Density of metal per cm³ = 7.7 g
Weight of tube = 7.8 g × 4085.71
= 31868.538 g
= 31.868 kg
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