The thimble of a screw gauge has 50 division advances 3mm when the screw is turned through six rotations. What is the least count of the screw gauge
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Given -
Number of circular division - 50
Linear distance moved to complete whole rotation- 3mm
therefore , pitch of tge screw gauge = 1/2×3
= 3/2 mm
Least count of screw gauge -pitch /no of circular div
=3/2 /50
=3/2×1/50
=3/100
=0.03
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