Question

The thimble of a screw gauge has 50 division. The spindle advances 1mm when the screw is turned through two revolutions. What is the pitch of screw gauge? What is the least count of the screw gauge

Answer 1

Given,

Number of circular division=50 divisions

Linear distance moved in two complete rotation=1mm

Therefore,

(i)  Pitch of the screw gauge

pitch=  1/2*1mm

         =0.5 mm

(ii)  Least count of the screw gauge

Least count=     pitch ÷no of circular div             

                   =                0.5/50

                        =         5/10*5

                         =   0.01mm

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Answer 2

Answer:0.5mm

Explanation:given no of head scale divisions=50

We know that least count of a screw guage is 0.01mm

Then

Least count=pitch of the screw/no.of head scale divisions

Then pitch of the screw=L.C*no.of head scale divisions

=0.01*50

=0.5mm