Question

The thin rod shown below has mass m And length l . A force F acts at one end as shown and the rod is free to rotate about the other end in the plane of force. Initial angular acceleration of rod is

Answer 1

The Initial angular acceleration of rod is α = 3F / 2ML

Explanation:

Torque " τ" = lα

τ = LF sin θ

l = 1/3 ML^2

α = T /l

α = LF sin θ / 1/3 ML^2

α = 3F / 2ML

Thus the Initial angular acceleration of rod is α = 3F / 2ML

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Torque (t) acting on a body in the interval 0 to T seconds is shown in figure. Angular impluse on the body in this interval is​ ?

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Answer 2

Explanation:

preety simple application of moment of inertia