The third and 7th of an AP are 27and the 91 representatively find first term and the common difference
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Step-by-step explanation:
Given:
19=a+5d
41=a+16d
Tn =a+(n−1)d
Where a is the first term, d is the common difference and Tn denotes the n-th term of an AP.
Solving the above equations gives: d=2,a=9
Therefore,
T40 =9+39⋅2= 87
solution=87
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