The third line in Balmer series corresponds to an electronic transfer between which Bohr's orbit in hydrogen
A.5to3
B.5to2
C.4to3
D.4to2
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2
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Since, the inner orbit is 2 and from the given question we get to know that transition is required for the third line of balmer series hence the outer orbit must be n2=2+3 = 5. Thus, the transition must be from 2 to 5.
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don't know sorry really appreciate you r wirk
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