Question

the third line in Balmer series corresponds to an electronic transition between which bohr orbits in hydrogen​

Answer 1

Balmer series have n1 = 2 nd the given line is third line, so n2 = 2 + 3 =5.

Thus the third line of Balmer series corresponds to n1= 2 & n2 = 5

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Answer 2

Answer:

As the balmer series has its inner orbital of n1=2 hence the outer orbital must be 2 + the number of lines formed by the corresponding transition as in case here is the transition between the bohr orbits of the third spectral line.

Since, the inner orbit is 2 and from the given question we get to know that transition is required for the third line of balmer series hence the outer orbit must be n2=2+3 = 5.

Thus, the transition must be from 2 to 5.