Chemistry, asked by kush3288, 10 months ago

The third line of the Balmer series, in the emission
spectrum of the hydrogen atom, is due to the
transition from the
(a) fourth Bohr orbit to the first Bohr orbit
(b) fifth Bohr orbit to the second Bohr orbit
(c) sixth Bohr orbit to the third Bohr orbit
(d) seventh Bohr orbit to the third Bohr orbit

Answers

Answered by soniasinghal1913
12

Answer:

In the atomic emission spectra of the hydrogen atom, the emission lines from an excited state n

th

Bohr orbit ($$n>2$$) to second Bohr orbit (n=2) is called Balmer series. Thus emission from $$n>2$$ to n=2 constitutes the various spectral lines of the Balmer series.

For the third line of Balmer series the transition should take place from n=2+3=5 to n=2 Bohr orbit i.e. from fifth Bohr orbit to second Bohr orbit.

Explanation:

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