The third member of the alkyne homologous series
Answers
Answered by
0
Answer:
Butyne
Explanation:
Alkyne members have one or more triple bond.
So, at least 2 carbon atoms should be there.
Therefore, 1st member = Ethyne
2nd member = Propyne
3rd member = Butyne
Answered by
2
Answer:
c4 h8 is the ans of this question
Explanation:
Similar questions