Question

the third one is here pls ye to answer karo
In the given figure ,AD is the bisector of exterior angle A of triangle ABC . Seg AD intersects the side BC produced in D .Prove that BD/CD = AB/AC​

Answer 1

$\large\boxed{\fcolorbox{blue}{yellow} {Answer}}$

$\large\boxed{\fcolorbox{blue}{yellow} {See the attachment }}$

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